Teachers Eligibility Test - Paper 2
Class – VI Mathematics
NUMBER SYSTEM
Use of Large Numbers in Daily Life Situations
Example: 1
In an exhibition, the number of tickets
sold on the first, second, third and fourth days are 1, 10,000, 75,060, 25,700
and 30,606 respectively. Find the total number of tickets sold on all the 4
days.
Solution:
Number of
tickets sold on the first day = 1,
10,000
Number of
tickets sold on the second day = 75,060
Number of
tickets sold on the third day =
25,700
Number of
tickets sold on the fourth day = 30,606
Adding
all the above,
The total number of tickets sold on
all the 4 days = 2,41,366.
Example: 2
In a year, a whole-sale paper firm sold
6, 25,600 notebooks out of 7, 50,000 notebooks. Find the number of notebooks
left unsold.
Solution:
Number of
notebooks in the store = 7, 50,000
Number of
notebooks sold = 6, 25,600
Subtracting
the above,
Number
of notebooks unsold = 1, 24,400.
Example: 3
In
a mobile store, the number of mobiles sold during a month is 1250. Assuming
that the same numbers of mobiles are sold every month, find the number of
mobiles sold in 2 years.
Solution:
Number of
mobiles sold in 1 month = 1250
1 year = 12
months
2 years = 2 × 12
= 24 months
Number
of mobiles sold in 12 months =1250 × 12
=15,000
Number of
mobiles sold in 24 months = 1250 × 24
= 30,000
Number of
mobiles sold in 2 years = 30,000.
Example: 4
If ` 10,00,000 was distributed in a
Government scheme to 500 women in the Self Help Groups, then find the amount
given to each woman.
Solution:
Amount to be given to 500 women = 10,00,000
Amount
given to each woman = 10,00,000 ÷ 500
= 2000
Each woman in
the Self Help Group was given 2000.
Order of Operations
BIDMAS
Valli
and her four friends went to a butter milk shop. Each had a cup of butter milk
and paid 30, assuming that the cost of one cup of butter milk to be 6. But the
shop keeper told that the cost of butter milk had increased by 2. Then, Valli
decided to give 2 more and paid 32. But the shop keeper claimed that she had to
pay 40. Who is correct?
Valli
calculated as = (5x6)+2 =30 + 2= 32
Shop
keeper calculated as, = 5x (6+2)
=5x8
=40
The
amount 40 claimed by the Shop keeper is correct. This confusion can be avoided
by using the brackets in the correct places like 5 × (6 + 2).
The
rule of order of operations is called as BIDMAS.
|
Expansion of BIDMAS |
|
|
B |
Bracket ( ) |
|
I |
Indices (you will learn it
later) |
|
D |
Division ÷ or / |
|
M |
Multiplication × |
|
A |
Addition + |
|
S |
Subtraction − |
Example: 5
Simplify: 24 + 2
× 8 ÷ 2 + 1
Solution:
Given, 24 + 2 ×
8 ÷ 2 – 1 (first
we solve the division ÷)
=24 + 2 ×
4 − 1 (second we solve the multiplication)
=24 + 8 – 1 (we solve the addition)
=32 –
1 (then subtract)
=31
Hence,
24 + 2 × 8 ÷ 2 + 1 = 31
Example: 6
Simplify:
20 + [8 × 2 + {
Solution:
Given,
20 + [8 × 2 + {
=20 + [8 × 2 +
{18 − 10 ÷ 5}] (bar completed first)
=20 + [8 × 2 +
{18 − 2}] (÷ completed
second)
=20 + [8 × 2 + 16] ({ } completed third)
=20 + [16 +
16] (×
completed fourth)
=20 + 32 ([ ] operation
completed fifth)
=52 (+
completed last)
Hence,
20 + [8 × 2 + {
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